Partial Match: Difference between revisions
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(Created page with "{{DISPLAYTITLE:Partial Match (Partial Match)}} == Description == In the Partial Match problem, we are given a "database" of $n$ binary strings, and a list of $n$ "queries" which are strings in $\{0,1,?\}^*$. (Here, "?" represents a wildcard.) We say that a query $q=q_1,...,q_d$ matches a string $x=x_1,...,x_d$ if for all $i=1,...,d$, if $q_i$ in $\{0,1\}$ then $q_i = x_i$. Output: Determine for all $n$ queries, which of them match some string in the database. == Param...") |
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== Parameters == | == Parameters == | ||
n: number of binary strings/queries | |||
d: length of strings/queries | |||
d: length of strings/queries | |||
== Table of Algorithms == | == Table of Algorithms == |
Revision as of 12:04, 15 February 2023
Description
In the Partial Match problem, we are given a "database" of $n$ binary strings, and a list of $n$ "queries" which are strings in $\{0,1,?\}^*$. (Here, "?" represents a wildcard.) We say that a query $q=q_1,...,q_d$ matches a string $x=x_1,...,x_d$ if for all $i=1,...,d$, if $q_i$ in $\{0,1\}$ then $q_i = x_i$. Output: Determine for all $n$ queries, which of them match some string in the database.
Parameters
n: number of binary strings/queries
d: length of strings/queries
Table of Algorithms
Currently no algorithms in our database for the given problem.
Reductions TO Problem
Problem | Implication | Year | Citation | Reduction |
---|---|---|---|---|
OV | If: to-time: $n^{2-\epsilon}*poly(d)$ for some $\epsilon > {0}$ Then: from-time: $n^{2-\epsilon'}*poly(d)$ for some $\epsilon' > {0}$ |
2020 | https://people.csail.mit.edu/virgi/6.s078/lecture6-post.txt | link |
Reductions FROM Problem
Problem | Implication | Year | Citation | Reduction |
---|---|---|---|---|
OV | If: to-time: $n^{2-\epsilon}*poly(d)$ for some $\epsilon > {0}$ Then: from-time: $n^{2-\epsilon'}*poly(d)$ for some $\epsilon' > {0}$ |
2020 | https://people.csail.mit.edu/virgi/6.s078/lecture6-post.txt | link |